Polar Curves and their Moving Frames
Now we will study satellite
motion using polar coordinates. We will show in Harmony of the Spheres
that for a single satellite, ignoring all others, if we could assume the Earth
did not move, then the satellite must move in a plane that contains
the Earth if it is governed by Newton's gravitational law. For now, we will
simply assume that the satellite moves in a plane. Of course, Newton was interested
in the motion of the planets around the Sun, but the principle will be the same.
The effect of the satellite
on the Earth is, however, not entirely negligible -- especially if that satellite
is the Moon! The Earth does wobble just a little because of the satellite's
pull. Newton therefore imagined a fictitious "center of mass" of the
satellite-Earth system (recall our hockey puck experiment in the introduction)
and showed that his slightly modified equations with that center of mass at
the origin (instead of the Earth) gave the Keplerian prediction of elliptical
orbits. Now this wobble is in any case so vanishingly small for Earth that we
may safely ignore it in our calculations, and we will. I only mention the correction
for completeness.
So we may use a 2-dimensional polar system of coordinates
to describe the motion of the satellite around the Earth. We will, naturally,
place the Earth at the origin of this system of coordinates. For the planets
orbiting the Sun, this polar plane is essentially the observed ecliptic. We
therefore assume that the "satellite," moving under the influence
of gravity alone, traces a plane curve parametrized by an angle q,
|
|
We will write
instead of the more correct (but pedantic)
.
We do not know what the polar function r(q) is. Our job will be to find it. We will prove
later using Newton's law, that if we assume the satellite is not moving on a
straight line away from or towards the Earth, at a single point in time,
then it will never move that way at any instant of the past or future,
and in fact, r(q) will never be 0.
The next series of pictures
and equations will sum up the kinematics of our problem. That is, assuming
only that the planet moves in a plane, and making no assumption at all yet about
the nature of the accelerations, we will say all that we can say about the motion.
After that, we will introduce the dynamics of the problem. It is only
when we reach that point that the role of the gravitational force comes
into play. So, until we say otherwise, all remarks below are quite general,
and do not depend on Newton's gravity. But remember that the fact that motion
is in a plane will depend on the property of the gravitational law that the
force of attraction (essentially the acceleration) is always towards the Earth.
Now the trick is to define
a new polar curve, u(q) in the following
way. For each angle q, there is a point
along the curve at that angle. Its polar coordinates are:
, and its Cartesian coordinates are:
|
|
where
|
|
|
|
If we connect this point to
the origin (the Earth) by an imaginary line, that line intersects the unit
circle, the set of points at distance 1 from the origin, in a unique
point (since r(q) is never 0). This point, for each q, is denoted
.
So the curve
is the projection of the curve (x(q),y(q))
onto the unit circle. We then have an important and rather obvious identity
for
|
|
the Cartesian curve that describes the planetary orbit as a function, not of time, but of q.
If we represent the polar
curve
also in Cartesian coordinates then
![]()
We represent the point on the unit circle with the symbol:
, which is, apparently, nothing but a "wrapping function" discussed
in most trigonometry texts,
|
|
so we may write, finally:
|
|
The important point here is
that
has two Cartesian components for each angle q. It is a point on the unit circle.
We are also assuming that we can actually use
to parametrize the curve
. It is important to know that as time increases,
increases. The planet does not "back up" as Ptolemy thought. Actually
Kepler's second law indicates that this should be so. This is why.
|
|
as functions of time. Thus (as you will show below)
|
|
Now,
|
|
so, since
is a function of time, it is clear that if
became 0, then at that time,
would be 0 also.
But then we would have
|
|
and so velocity would be a multiple of position. But we have ruled this possibility
out. So from now on, differentiation will be with respect to the variable q,
rather than with respect to time. In particular, we may calculate the derivative
of
.
|
|
by differentiating each coordinate separately as we do for all curves. This
gives a new curve that we shall call ![]()
|
|
Question 1: Show that
|
|
and also show that for each
,
is perpendicular to
.
End of Question
Summing up Newton's observations
so far, we have plane curves, parametrized now by the angle q,
|
|
|
|
|
|
all associated with our satellite. Our job is to learn what the function r(q) is.
Question 2: Show that if
is a real-valued function of
,
and if
is a plane curve, then we may define a new plane curve:
![]()
by multiplying each of the coordinates of
by
for each
.
Explain carefully why we have an analog of the "product formula"
|
|
End of Question
The pair of vectors
are perpendicular to each other, and each has length 1. They define a "moving
frame" along the curve
.
Imagine that you ride along the orbit, and at each point
,
you construct the perpendicular pair:
(blue) and
(dark red) at that point, as pictured below:
The bright red vector
is the "velocity" as we traverse the curve by covering equal angles
in equal times in the counterclockwise sense.
Now Newton's ingenious idea
is to use this "moving frame" as our reference for the measurement
of velocities. We measure the components of velocity with respect to this rotating
frame at each "time"
.
Now satellites generally do not traverse equal angles in equal times. Kepler's
second law says that they do something more interesting, as we shall see. So
we are not pretending that this curve, parametrized as it is, by
, represents an actual satellite orbit on this page, although our geosynchronous
satellite will behave that way. On the next page, we will simulate more natural
satellite orbits using Newton's equations! Here, we just want to present the
basic idea.
Now, if we represent the
velocity at the point above in this moving frame we will see a picture like
this:
Imagine then, that as you ride the orbit, you record how the velocity
(bright red vector) changes as
changes. We will trace the curve that
makes in the exercise on this page. You will be able to provide your own examples,
but in general it will have no easily recognizable form:
This is not so with real satellites, as we shall see.
Now,
with these pictures understood, and with the ones you will create yourself,
we are prepared to derive some new relations for this velocity curve.
To make the analysis more
realistic, and to prepare for the study of real satellites, we let q
itself be an increasing function of time t. That is, for the satellite,
the angle q increases with t.
So we may write the curve that describes the planet's position also as
|
|
Differentiation with respect to time, t, will now be denoted by a "dot"
rather than a "prime", but remember that
|
|
First, let us calculate the
velocity,
|
|
|
|
This is why. We calculate
|
|
using the chain rule and our generalized product rule derived above. This is
|
|
but by an earlier definition:
|
|
Thus, in the
coordinates of our moving frame:
|
|
Acceleration of a Curve in Moving Frame Coordinates
Now we differentiate again.
Question 3: Show that the acceleration of the planet is given by
|
(0.1) |
|
or, in the
coordinates of our moving frame:
|
|
Do the detailed calculation using the chain rule as above. The first coordinate:
|
|
is called the "radial" component of acceleration.
For example, if r is constant and
is constant (we are not considering gravity yet) then
is the speed ![]()
You may recognize that this radial component then becomes the entire acceleration.
|
|
which is called the "centripetal acceleration" for uniform circular motion. This will in fact represent the motion of our geosynchronous satellite that moves at constant speed and at constant distance from the Earth. The other terms have similar interpretations.
End of Exercise
This finishes the discussion
of the kinematics of satellite motion. On the next page, we will begin to study
the dynamics, following Newton, and assuming that the motion is governed by
his gravitational law.
Exploration: Graphing polar curves
On this page, you are invited to experiment with a few of these ideas. First, use the control panel
to define a polar curve:
. We use A for the angle, here measured in radians.
Initially, we supply R
= 2/(1+0.5*cos(A)), which, as you may recall from the previous page,
is an ellipse with the origin at one focus. This ellipse has eccentricity 0.5.
If you would like to work with more exotic polar curves, just enter the curve
in the top yellow field. You may also specify the interval on which A
is defined.
The curve will be traversed in equal steps in A, and you can define the size of the step in the Step for A field.
Next, press Graph Curve
to see the curve in the large Graph2D on the right. You may now watch the frame
move around the curve by repeatedly pressing the Plot Next Point button.
The bright red vector is the "velocity" vector:
.
On this page,
.
In the left hand Graph2D you
will see the curve
referred to our moving
frame:
traced out as you step along. It might be interesting to examine this for a
circle, given, say, by R = 2. Now change it to a slightly eccentric
ellipse, say, 2/(1+0.08*cos(A)). Do you see what is going on? We will
have much more to say about this picture on the next page, when we begin to
study the dynamics of satellites.
Now, if you want to speed things up, just press the Animate ! Button.
and watch the show!